NCERT Solutions for Class 4 Math Chapter 6 The Junk Seller

NCERT Solutions for Class 4 Maths Chapter 6 The Junk Seller provided here is extremely helpful in revising complete syllabus and getting a strong base on it. NCERT 4th Class Maths The Junk Seller all questions are solved with detailed explanation available for students. In this article we had given of NCERT solutions for The Junk Seller Class 4 Maths step by step solution for each and every question of the chapter. These solutions will also help you with your homework. Best teachers across the India created NCERT solutions for Class 4 Maths Chapter 6 The Junk Seller according to curriculum and pattern of syllabus as per guidelines of NCERT (CBSE) Books.

4th Class NCERT Maths Chapter 6 The Junk Seller

Name of Organization	NCERT
Name of Class	4th Class
Name of Subject	Maths
Name of Chapter	Chapter 6
Name of Content	The Junk Seller
Name of Category	NCERT Solutions
Official site	http://ncert.nic.in/

Chapter 6 The Junk Seller covers numerous Questions and answers from all topics and sub-topics which are given below

Page No 60:

Question 1:

• What about you? Do you also find Maths difficult? • What is the most difficult thing in your Maths books? ________ • What do you think is the easiest lesson? ________

Answer:

Disclaimer: The answer may vary from student to student based on his/her experience. It is highly recommended that the students prepare the answers on their own.

Page No 61:

Question 1:

Find out: how much for a cup of tea?

Ask people and find out the cost of a cup of tea • at a tea stall ____________ • at a hotel _______________

Answer:

Disclaimer: The purpose of this section is to make the students observe their surroundings. The answer may vary from student to student based on his/her experience. It is highly recommended that the students prepare the answers on their own.

Question 2:

If a person who runs a tea stall earns Rs 30 in a day, how much will he earn in 10 days? _____________

And in a month? _______________ How did you get the answer? Discuss.

Answer:

Earning of the man in 1 day = Rs 30 Earning of the man in 10 days = Rs 30 × 10 = Rs 300

We do it in the following manner:

1 times 30 is 30. 10 times 30 is 300.

Suppose there are 30 days in a month. Earning of the man in a month or 30 days = Rs 30 × 30 = Rs 900 We do it in the following manner: 3 times 30 is 90. 30 times 30 is 900.

Question 3:

Hariya and Babu want to buy a handcart for Rs 300.

Who has to pay back more — Hariya or Babu? _____________

Answer:

Hariya took a loan of Rs 300 from a bank for 6 months to buy a handcart. He pays Rs 51 every month to the bank. Money paid back by Hariya to the bank in 1 month = Rs 51 Money paid back by Hariya to the bank in 6 months = Rs 51 × 6 = Rs 306

We do it in the following manner: 6

×50 = 300 6

×1 = 6 So,

300+6306 So, Hariya paid Rs 306 to the bank after 6 months.

Babu took a loan of Rs 300 from Chunnilal for 6 months to buy a handcart. He paid Rs 360 to Chunnilal after 6 months. Thus, Babu has to pay back more than Hariya for buying the handcart.

Page No 62:

Question 1:

I have 9 rickshaws of my own. I give the rickshaws on rent. each for Rs 20 a day. On Sundays I do not take any money for them. • In a week how much does Kiran earn from one rickshaw?

Answer:

We know that there are 7 days in a week. Earning of Kiran from 1 rickshaw per day = Rs 20 Earning of Kiran from 1 rickshaw for 7 days = Rs 20 × 7 = Rs 140

We do it in the following manner: 2 times 7 is 14. 20 times 7 is 140.

Now, On Sunday, Kiran does not take any money for the rickshaws. Therefore, earning of Kiran from 1 rickshaw for 6 days = Rs 140 − Rs 20 = Rs 120 We do it in the following manner:

140-20120¯So, Kiran will earn Rs 120 in a week from 1 rickshaw.

Page No 63:

Question 1:

Do it mentally and write the answers.

2 × 6 = __________
20 × 6 = __________
2 × 60 = __________
3 × 42 = __________
4 × 80 = __________
4 × 81 = __________
9 × 25 = __________
31 × 9 = __________

Answer:

We do it in the following manner: 2 times 6 is 12. 20 times 6 is 120.

We do it in the following manner: 3

×40 = 120 Also, 3

×2 = 6 So, 120+6126¯

We do it in the following manner: 4 times 8 is 32. 4 times 80 is 320.

We do it in the following manner: 4

×80 = 320 Also, 4

×1 = 4 So, 320+4324¯

We do it in the following manner: 9

×20 = 180 Also, 9

×5 = 45 So, 1180+45225¯

We do it in the following manner: 30

×9 = 270 Also, 1

×9 = 9 So, 270+09279¯

Question 2:

Look up the rate list to see today’s rates. Help Kiran to find out the cost of the junk. • How much will Kiran pay for 31 kg newspaper? 1 kg newspaper costs Rs 5. 30 kg cost Rs 5 × 30 = Rs 150. So for 31 kg she pays Rs _____. • How much will Kiran pay for 42 kg newspaper? • Also find the cost of: (a) 22 kg of plastic (b) 23 kg of waste paper (c) 12 kg of iron

Rate-List
Kind of Junk	Price of 1 Kg
1. Waste Paper	Rs 4/-
2. Newspaper	Rs 5/-
3. Iron	Rs 12/-
4. Brass	Rs 170/-
5. Plastic	Rs 10/-

Can you do this without writing? Guess the total money Kiran will pay to the junk collectors. Will it be — More than 600? — Less than 600?

Answer:

Cost of 1 kg newspaper = Rs 5

Cost of 31 kg newspaper = Rs 5 × 31 = Rs 155

We do it in the following manner: 5 × 30 = 150 5 × 1 = 5 So, 150+5155

Cost of 42 kg newspaper = Rs 5 × 42

= Rs 210 We do it like this: 5 × 40 = 200 5 × 2 = 10 So, 200+10210 (a) Cost of 1 kg plastic = Rs 10 Cost of 22 kg plastic = 22 × Rs 10 = Rs 220

We do it in the following manner: 22 × 1 = 22 22 × 10 = 220

(b) Cost of 1 kg waste paper = Rs 4 Cost of 23 kg wastepaper = Rs 4 × 23 = Rs 92

We do it in the following manner: 4 × 20 = 80 4 × 3 = 12 So, 80+1292(c) Cost of 1 kg iron = Rs 12 Cost of 12 kg iron = Rs 12 × 12 = Rs 144

We do it in the following manner:

Add the numbers in the box

1002020+4144Total money paid to junk collectors will be = Rs 155 + Rs 210 + Rs 220 + Rs 92 + Rs 144 = Rs 821

1251521022092+144821So, the total money paid to the junk seller is more than Rs 600.

Page No 65:

Question 1:

• Kiran bought 1 kg plastic for Rs 10, but sold 1 kg plastic for Rs 12. How much money does she earn on selling 1 kg plastic? Rs _______ So, how much money does she earn for 63 kg? Rs _______

Answer:

Cost price of 1 kg plastic = Rs 10 Selling price of 1 kg plastic = Rs 12 Profit on selling 1 kg plastic = Rs (12 − 10) = Rs 2 Profit on selling 63 kg plastic = Rs 2 × 63 = Rs 126

We do it in the following manner: 2 × 60 = 120 2 × 3 = 6

120+6126Hence, Kiran will earn Rs 126 on selling 63 kg plastic.

Page No 66:

Question 1:

• How much money will Dinu pay for 32 kg iron? • Kiran buys 1 kg iron for Rs 12 but sells it for Rs 14. How much does she earn when she sells 32 kg iron? Rs _______

Answer:

• Cost of 1 kg iron = Rs 14 Cost of 32 kg iron = Rs 14 × 32 = Rs 448 We do it like this: Add the numbers in the box

30012020+8448So, Dinu will have to pay Rs 448 for 32 kg iron.

Cost of 1 kg iron for Kiran = Rs 12

Selling price of 1 kg iron = Rs 14 Profit on selling 1 kg iron = Rs (14 − 12) = Rs 2 Profit on selling of 32 kg iron = Rs 2 × 32 = Rs 64

We do it in the following manner: 2 × 30 = 60 2 × 2 = 4

So, 60+464

Thus, Kiran earns Rs 64 on selling 32 kg iron.

Question 2:

I bought 1 kg newspaper for Rs 5, but sold it for Rs 6. How much money did I earn by selling 152 kg of newspaper? ________

Answer:

Cost of 1 kg newspaper = Rs 5 Selling price of 1 kg newspaper = Rs 6 Profit on selling 1 kg newspaper = Rs (6 − 5) = Re 1 Profit on selling 152 kg newspaper = Re 1 × 152 = Rs 152 I earned Rs 152 on selling 152 kg of newspaper.

Question 3:

How much money will Dinu pay for 4 kg brass? _________ Guess the answer first.

Answer:

Cost of 1 kg brass = Rs 180 Cost of 4 kg brass = Rs 4×180 = Rs 720 We will do it as follows:

Add the numbers in the box

400+320720Thus, Dinu will pay Rs 720 for 4 kg brass.

Page No 67:

Question 1:

First guess the answer and then calculate: (a) 37 × 18 = (b) 45 × 24 = (c) 69 × 52 = (d) 77 × 55 = (e) 142 × 5 = (f) 382 × 3 = (g) 2 × 175 = (h) 4 × 206 =